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mdlnlcs
02.03.2020 •
Mathematics
According to national data, about 14% of American college students earn a graduate degree. Using this estimate, what is the probability that exactly 26 undergraduates in a random sample of 200 students will earn a college degree? Hint: Use the normal approximation to the binomial distribution, where p = 0.14 and q = 0.86. (Round your answer to four decimal places.)
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Ответ:
Using the probability mass function we can find the probability required
We need to check the conditions in order to use the normal approximation.
We assume independence in the events
So we see that we satisfy the conditions and then we can apply the approximation.
If we appply the approximation the new mean and standard deviation are:
So then we can approximate the normal with![X \sim N(\mu =28, \sigma =4.907)](/tpl/images/0531/0682/a679b.png)
But for this case since we have a continuous distribution with this approximation we can't find
since the are below a point is 0, w can find
or
but not
using the normal approximation.
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Solution to the problem
For this case we have the following distirbuion for X the number of undergraduates
Using the probability mass function we can find the probability required
We need to check the conditions in order to use the normal approximation.
We assume independence in the events
So we see that we satisfy the conditions and then we can apply the approximation.
If we appply the approximation the new mean and standard deviation are:
So then we can approximate the normal with![X \sim N(\mu =28, \sigma =4.907)](/tpl/images/0531/0682/a679b.png)
But for this case since we have a continuous distribution with this approximation we can't find
since the are below a point is 0, w can find
or
but not
using the normal approximation.
Ответ:
14=x
Step-by-step explanation: