Mathematics: Acone has a diameter of 22 inches and a height of 4.5 inches. what is the volume of the cone to the nearest tenth in³ ? use 3.14 to approximate pi. 49.5 in³ 121.4 in³ 569.9 in³ 1024.4 in³

Acone has a diameter of 22 inches and a height of

Ответ:

chubbyxturtle

17.01.2022

Mathematics

Your Answer would be Option C

Step-by-step explanation:

We know, Volume of a Cone = πr² h/3v = 3.14 * (11)² * 4.5/3v = 3.14 * 121 * 1.5v = 569.91 in³

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Ответ:

miya2579

09.05.2022

Mathematics

when y = -1.07, x = 1.105

when y = 0.698, x = -1.547

The explanation to the above solutions is as follows;

Given;

2x + 3y + 1 = 0 -----(1)

y² + 6xy + 6 = 0 ---- (2)

To solve for x and y;

From equation (1) above, make x the subject of the formula;

$2x +3y + 1 = 0\\\\2x = -3y-1\\\\x = \frac{-3y-1}{2} \\\\Substitute \ the \ value \ of \ x\ into \ equation \ (2)\\\\y^2 + 6xy + 6 = 0\\\\y^2 + 6( \frac{-3y-1}{2})y + 6 = 0\\\\y^2 -9y^2-3y+ 6 = 0\\\\-8y^2 - 3y + 6 = 0\\\\multiple \ through \ by \ - 1\\\\8y^2 +3y - 6 = 0\\\\solve \ the above \ quadratic \ equation \ using \ formula \ method\\\\a = 8, \ b = 3, \ c = - 6\\\\y = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\y = \frac{-3 \ \ +/- \ \ \sqrt{(3)^2 - 4(8\times -6)} }{2\times 8}\\\\$

$y = \frac{-3 \ \ +/- \ \ \sqrt{201} }{16}\\\\y = \frac{-3 \ \ +/- \ 14.177}{16} \\\\y = \frac{-3 -14.177}{16} \ \ \ or \ \ \ \frac{-3 +14.177}{16} \\\\y = - 1.07 \ \ or \ \ \ 0.698$

Now solve for the values of x

$x = \frac{-3y - 1}{2} \\\\when \ y = -1.07, \ \ \ x = \frac{-3(-1.07) -1}{2} = 1.105\\\\when \ y = 0.698, \ x = \frac{-3(0.698) -1}{2} = -1.547$

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Acone has a diameter of 22 inches and a height of 4.5 inches.
what is the volume of the cone to the nearest tenth in³ ?
use 3.14 to approximate pi.

49.5 in³

121.4 in³

569.9 in³

1024.4 in³

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