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rileyeddins1010
10.10.2019 •
Mathematics
Ageometry class is asked to find the equation of a line that is parallel to y – 3 = −(x + 1) and passes through (4, 2). trish states that the parallel line is y – 2 = –1(x – 4). demetri states that the parallel line is y = –x + 6.
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Ответ:
the equation of a line with slope of m and passing through point (x1,y1) is
y-y1=m(x-x1)
we are given
y-3=-1(x+1)
slope=-1
we don't need the point
we want it to pass through (4,2)
x1=4
y1=2
y-2=-1(x-4)
trish is right
solve for y
y-2=-x+4
y=-x+6
both are correct
Ответ:
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Step-by-step explanation:
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