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derbraz4588
04.07.2020 •
Mathematics
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:
420 425 427 427 432 433 434 437 439 446 447 448 453 454 465 469
Suppose the sample is from a normal population.
(a) Calculate a 95% confidence interval for the population mean, and interpret it.
(b) Calculate a 95% upper confidence bound for the population mean, and interpret it.
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Ответ:
(a) A 95% confidence interval for the population mean is [433.36 , 448.64].
(b) A 95% upper confidence bound for the population mean is 448.64.
Step-by-step explanation:
We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:
420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. =
~ ![t_n_-_1](/tpl/images/0701/3532/5cbec.png)
where,
= sample mean =
= 441
s = sample standard deviation =
= 14.34
n = sample size = 16
Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.
So, 95% confidence interval for the population mean,
is ;
P(-2.131 <
< 2.131) = 0.95 {As the critical value of t at 15 degrees of
freedom are -2.131 & 2.131 with P = 2.5%}
P(-2.131 <
< 2.131) = 0.95
P(
<
<
) = 0.95
P(
<
<
) = 0.95
95% confidence interval for
= [
,
]
= [
,
]
= [433.36 , 448.64]
(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].
The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.
(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.
Ответ:
30 desserts
Step-by-step explanation:
60/20=30
90/30=30 desserts