Andrew has only one white and black socks in a drawer. The probability of him pulling out a black sock is 1/5. What is the likelihood of Andrew randomly pulling out a white sock?

4/5

Step-by-step explanation:

Andrew has just two possibilities: pulling out a white sock or pulling out a black sock.

If the probability of Andrew pulling out a black sock is 1/5, knowing that the sum of both probabilities need to be 1, we can calculate the probability of pulling out a white sock if the following equations:

Prob_white + Prob_black = 1

Prob_black = 1/5

So:

Prob_white + 1/5 = 1

Prob_white = 1 - 1/5 = 4/5

The probability of Andrew pulling out a white sock is 4/5.

11 shirts and 4 pants.

Step-by-step explanation:

Let x be the number of shirts and y be the number of pants,

So, the total shirts and pants = x + y

According to the question,

x + y = 15 (1),

Also, shirts are 7 more than pants,

i.e. x = y + 7

Substitute this value in equation (1),

y + 7 + y = 15

2y + 7 = 15

2y = 8

⇒ y = 4

Again from equation (1),

x + 4 = 15

⇒ x = 11

Hence, she bought 11 shirts and 4 pants.