asims13
22.08.2019 •
Mathematics
Answer asap! important! must be correct! giving out points!
john stated that when you add an even and an odd integer the answer will be odd. use these numbers to answer the questions: –13, –8, 16, 23, –7
is john’s statement always true, sometimes true, or always false? write two equations to support your answer.
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Ответ:
an odd is 1 more than an even so 2n+1 is odd
so even+odd=2n+2n+1=4n+1=
we see 2 2n's in there which are even
(even)+(even)+1
we know that even+even=even try that withe any 2 even numbers
then +1 means it's odd so therefor it is always true
Ответ:
-13 +16 = 3 odd+even = odd
-7 + 16 = 9
how about -13 + -7 = -20
-8 + 16 = 8
It looks like
even + even = even
odd + odd = even
even + odd = odd
So, we only get an odd result in this case. It seems that it is always true.
Ответ:
Step-by-step explanation:
you have to add the pricethen you find for one
if you have any questions comment on my question