jadacherry
03.07.2019 •
Mathematics
Aparabola y=1/2x^2-4x+21 can you me find the vertex form of this parabola and you : )
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Ответ:
First factor out the first 2 terms as follows:-
y = 1/2(x^2 - 8x) + 21
Now complete the square on x^2 - 8x:-
y = 1/2[ (x - 4)^2 - 16] + 21
y = 1/2(x - 4)^2 - 8 + 21
y = 1/2(x - 4)^2 + 13 Answer
Ответ: