Apilot flies a plane due west from 150 miles, then turns 42 degrees north of west for 70 miles. find the planes resultant distance and direction from the starting point.

This can be solve using cosine lawbut first let as solve the included angle in the triangle form
angle = 180 - 42angle = 138
c^2 = a^2 + b^2 - 2ab(cos angle)c^2 = 150^2 + 70^2 - 2(150)(70)cos(138)C^2 = 43006.04c = sqrt(43006.04)c = 207.37 mile
directionsin (x) / 70 = sin (138)/ 207.37sin x = 0.2259x = arcsin(0.2259)x = 13.05 degree north of west

No, Isiah is not correct. The GCF of the coefficients is 1, and there are no common variables among all three terms of the polynomial. 5b4 is a factor of -25a2b5 and -35b4, but not a3. Additionally, a2 is a factor of a3 and -25a2b5, but not -35b4.