Arectangle has an area of 30 m² and a perimeter of 34 m. what are the dimensions of the rectangle?

Length is l
width is w
l*w = 30
2l + 2w = 34

You can simplify the second equation to l + w = 17

Factors of 30:
30*1
15*2
10*3
6*5

Try adding each of these factors together, to find out which equals 17

30 + 1 = 31
15 + 2 = 17
10 + 3 = 13
6 + 5 = 11

So the dimensions of the rectangle are 15m * 2m

(1/2,-1.2)

Step-by-step explanation: