Arectangle has perimeter 68 meters, and its area is 280 sq-meters. find the dimensions of this rectangle. (for purposes of this problem only, the width is shorter than the length.)

Let one side be x and the other be y

Perimeter is 68 meters
2(x + y) = 68
x + y = 34
x = 34 - y (1)

Area = 280
xy = 280 (2)

Sub (1) into (2):

(34 - y)y = 280
34y - y² = 280
y² - 34y + 280 = 0
(x - 14)(x - 20) = 0
x = 14 or x = 20

The dimension  of this rectangle is 14 meters by 20 meters

Step-by-step explanation:

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