Mathematics: Arectangular yard is 20 yards wide and 40 yards long. it is surrounded by a thick hedge that grows on the border of the property, but completely within the boundaries of the yard. if the hedge covers an area of 171 square yards, what is the width of the hedge?

Arectangular yard is 20 yards wide and 40 yards - id20403929218, BaileyElizabethRay

hihudgins902

10.01.2022

$W_{h}= 4.275yd$

Step-by-step explanation:

Data

wide=20yd

length=40yd

Hedge area $A_{h}$ = $171yd^{2}$

If the area of rectangle is A=base * hight and our case L*W. then:

$A_{h}=171yd^{2}=40yd*W_{h}$

So $W_{h}=\frac{A_{h} }{L} =171yd^{2}/40yd=4.275yd$

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leslieperez67

23.11.2020

its b on edgen uity

Step-by-step explanation:

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