Mathematics: Arecursive rule for a geometric sequence is a1=8; an=3/4a n−1 . what is the explicit rule for this sequence?

Arecursive rule for a geometric sequence is a1=8;

Ответ:

sepdentalcare8774

17.01.2022

A(n) =(3/4)x a(n-1)

for n =1==> a₁ =8
Give for n, the value 2,3,4 etc.

for n=2==>a₂ = 3/4(a₁) = 3/4 (8) = 6
for n=3 ==>a₃ =3/4(a₂) = 3/4(6) = 9/2
for n=4 ==>a₄ =3/4(a₃) = 3/4(9/2)

and for n=n ==>a(n) =(3/4)(a(n-1)

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Ответ:

caggh345

24.11.2020

Mathematics

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