Mathematics: At 5: 45 p.m., a jet is located 108 mi due east of a city. a second jet is located 214 mi due north of the city. to the nearest tenth of a mile, what is the distance between the two jets? enter your answer as a decimal in the box.

The answer should be because 602163 is smaller than 620163...

At 5: 45 p.m., a jet is located 108 mi due east

elondamason

13.01.2022

The distance between the two jets is 239.7 miles.

Explanation:

Since we have given that

Distance at which first jet is located = 108 miles

Distance at which second jet is located = 214 miles

We need to find the distance between the two jets .

As it is form a "right triangle" so we can apply "pythagorus theorem", which is given as

$H^2=B^2+P^2\\\\H^2=214^2+108^2\\\\H^2=45796+11664\\\\H^2=57460\\\\H=\sqrt{57460}\\\\H=239.7\ miles$

Hence, the distance between the two jets is 239.7 miles.

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