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zack66828
25.07.2019 •
Mathematics
Atriangle has sides of length 11 m, 12 m, and 16 m. what is the measure of the angle opposite the side that is 16 m long? round to the nearest degree.
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Ответ:
the law of cosines formulas established
c²=a²+b²-2*a*b*cos C-----> cos C=[a²+b²-c²]/[2*a*b]
a=11 m
b=12 m
c=16 m
so
cos C=[11²+12²-16²]/[2*11*12]---> cos C=0.0341
C=arc cos (0.0341)-------> C=88.05°
see the attached figure
the answer is
the angle is 88°
Ответ:
88 degrees.
Step-by-step explanation:
We have been given that a triangle has sides of length 11 m, 12 m, and 16 m. We are asked to find the measure of the angle opposite the side that is 16 m long.
To find the measure of angle opposite to 16 m side, we will use law of cosines.
Upon substituting our given values in above formula we will get,
Now we will use inverse cos formula to solve for C.
Upon rounding our answer to nearest degree we will get,
Therefore, the measure of angle opposite to the 16 m long side is 88 degrees.
Ответ:
- 6n + 2 n = 20 - 16
- 4 n = 4
n = 4 / -4
n = - 1