Atriangular paddock has a road ab forming its hypotenuse. ab is 3 km long. the fences ac and cb are at right angles. if bc is 400 m longer than ac, find the area of the paddock in hectares.

Since the paddock assumes a rectangular shape the area is 1/2 * b * h. From Pythagorean AB^2 = BC^2 + AC^2 (3)^2 = (x + 0.4)^2 + x^2 9 = x^2 + 0.8x + 0.16 + x^2 So 2x^2 + 0.8x + 0.16 - 9 = 0 2x^2 +0.8x- 8.84 = 0 Using the quadratic formula The solutions are 1.911 and -2.31 The area therefore is area=1/2 * b * h =1.91*2.31/2 = 2.21km² 1hectare = 0.01km² 2.21km^2 = 221ha

X(2X-23)/(X-12)

Step-by-step explanation:

C = Chips = X

P = Pretzels

N = Nachos

First: X  (number of bags of Chips)

Second: 4P=X  (number of bags of pretzels)

Third: P=(P-3)N (number of bags of Nachos)

we need to simplify them and add them.

they bought:

X + 4P + (P-3)N in total

from the Nachos we can see: N= P/(P-3)

and from the Pretzels: 4P=X       X=4P     Therefore P=X/4

Also: N=(X/4)/((X/4)-3)

Replace:

X+ X + (X/4)/ ((X/4)-3)

2X+ 4/X/((X/4)-3) = 2X+(X/4)/((x-12)/4)

2X+X/4*4/(X-12)

2X+X/(X-12)

(2X*(X-12)+X)/(X-12)

(2X^2-24X+X)/(X-12)

X*(2X-23)/(X-12)