B + b + b = b *b*b
Find the value of b

±√3

Step-by-step explanation:

Given: If  b+b+b=b∗b∗b , what is b besides 0?  

3b =

Since I'm assuming we disregard  b=0  as a solution, we can divide both sides by b

3 =  

Now we need to be careful here since b could be positive/negative, when we square root both sides it will be absolute valued

3–√=|b|  

So either,  b = √3  or  b = –√3

hope this helps >~<