Based on the graph, determine if the discriminant is positive, negative, or zero.

Short answer 0

Step-by-step explanation:

We are intended to believe that the graph touches the x axis at exactly 1 place. If we write the vertex form of the equation, we get y = a*(x + 1)^2

The only problem left is what is "a"?

Use the y intercept to find that answer.

The y intercept from the graph is 0,2 which means that when x = 0, y = 2

x = 0

y = 2

2 = a(0 + 1)^2

2 = a(1)

a = 2

So the correct equation is y = 2(x+1)^2

Expand this to standard representation

y= 2(x^2 + 2x + 1) Remove the brackets

y=2x^2 + 4x + 2

What is the discriminate?

a  =  2

b = 4

c = 2

The discriminate formula is

sqrt(b^2 - 4*a*c)

sqrt(4^2 - 4(2*2)

sqrt(16 - 16)

sqrt(0)

0

Rule and The discriminate is ALWAYS zero when the quadratic graph just touches the x axis. Opening up or opening down does not matter.

0

Step-by-step explanation:

y = 2[x + 1]² → 2x² + 4x + 2

b² - 4ac → 4² - 4[2][2] >> 0

1616

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i think it is 487.5. i may be wrong tho. hope this helps!