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Dweath50
31.08.2020 •
Mathematics
Calculus 2 master needed; evaluate the integral PLEASE SHOW STEPS IF IM WRONG
I split off the sin^3 so i can use the pythag identity and allows for u substitution u=cosx du=-sinx dx -du=sin dx
I move the negative towards the outside of the integral. then i divide the terms by sqroot 2|||
I eventually get to a=1/2 b =5/2
did I miss anything? Or is this the final answer?
Solved
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Ответ:
Your process is indeed correct!
The full solution is:
Step-by-step explanation:
We want to evaluate the integral:
As you had done, we can rewrite our integral as:
Using the Pythagorean Identity, this is:
Now, we can make a substitution. Let u = cos(x). Then:
Substitute:
Simplify:
Rewrite:
By the Reverse Power Rule:
Simplify:
Back-substitute:
Ответ:
= - 2
+ 2 cos⁵/₂ (x) + C
5
Step-by-step explanation:
∫ sin³ (x) dx
= ∫ sin² (x) sin (x) dx
= ∫ (1 - cos² (x) sin (x) dx
= ∫ - 1 - u² du
√u
= ∫ - 1 + u³/₂ du
√u
= - ∫ 1 du + ∫ u³/₂ du
√u
substitute it back
= - 2 √u + 2 cos⁵/₂ (x)
5
add constant, therefore
= - 2
+ 2 cos⁵/₂ (x) + C
5
Ответ:
I think that it might be C. but I am NOT entirely sure though.
Step-by-step explanation: