Dweath50
Dweath50
31.08.2020 • 
Mathematics

Calculus 2 master needed; evaluate the integral PLEASE SHOW STEPS IF IM WRONG \int{sin^3x/\sqrt{cosx} } \, dx I split off the sin^3 so i can use the pythag identity and allows for u substitution u=cosx du=-sinx dx -du=sin dx \int{1-u^2/\sqrt{u}*-du } I move the negative towards the outside of the integral. then i divide the terms by sqroot 2||| -\int{(1/\sqrt{u} - u^2/\sqrt{u} )} \, du I eventually get to a=1/2 b =5/2 -2{cos^a x +2/5cos^b} \, dx did I miss anything? Or is this the final answer?

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