Can any one me if you do you will recive 30 points : ,(

1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25

2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13

3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33

4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19

8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99

9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20  20*4=80 20*5=100 4:5 =80:100

a. 80 and 100
b. you should be able to do this

10. so on a line is 180
a. 3:4:5  3+4+5=12  180/12=15
3*15=45  4*15=60  5*15=75
3:4:5 =45:60:75
the angles are 45 60 75

b. you should be able to do this from my work

1050

Step-by-step explanation: