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Tyasiapalair371
09.01.2020 •
Mathematics
Challenge: you have a 500-foot roll of chain link fencing and a large field. you want to fence in a rectangular
playground area. what are the dimensions of the largest such playground area you can enclose? what is the area
of the playground?
Solved
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Ответ:
Dimensions of the rectangular area:
x = 125 ft
y = 125 ft
A(max) = 15625 ft²
Step-by-step explanation:
Lets call x and y the wide and the height of the rectangular area. And P the perimeter
Then
A = x*y
And as we have 500 ft of fencing material
P = 2*x + 2*y ⇒ 500 = 2*x + 2*y ⇒ y = ( 500 - 2x ) / 2
y = 250 - x
Then rectangular area is:
A = x * y ⇒ A (x) = x* ( 250 - x ) ⇒ A (x) = 250*x - x²
Taking derivatives on both sides of the equation we get:
A´(x) = 250 - 2*x
A´(x) = 0 250 - 2*x = 0 ⇒ 2x = 250 ⇒ x = 125 ft
And y = 250 - x ⇒ y = 125 ft
We really got a square of side 125 ft
The area
A (max) = 125*125 = 15625 ft²
Ответ:
Then multiply 2727 by 2 to get 5454.