Mathematics: Compute the special products. (-3+5i)2

Compute the special products. (-3+5i)2

Ответ:

princessmaddiegigi

11.03.2022

Mathematics

we are given

(-3+5i)^2

we can expand it

(-3+5i)^2=(-3+5i)(-3+5i)

now, we can FOIL it

$(-3+5i)^2=-3\times -3-3\times 5i+5i\times -3+5i\times 5i$

now, we can simplify it

(-3+5i)^2=9-15i-15i+25i^2

we know that

i^2=-1

so, we can plug it

(-3+5i)^2=9-30i+25(-1)

(-3+5i)^2=9-30i-25

(-3+5i)^2=-16-30i ..............Answer

0,0(0 оценок)

Ответ:

lwilliams28

06.12.2020

Mathematics

A= 35° because 180°-80°-65°= 35°

b=50° because 180°-95°-35°= 50°

c=85° because 180°-95°= 85°

d=30° because 180°-65°-85°= 30°

For these you just have to remember that the sum of the angles of a triangle is 180°, and the same for a straight line.

0,0(0 оценок)

Compute the special products. (-3+5i)2

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question