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keepcalmands2930
13.12.2019 •
Mathematics
Confused on this for calc.
a particle moves along the x-axis with position function s(t) = e^sin(x). how many times in the interval [0, 2π] is the velocity equal to 0?
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Ответ:
2 times
Step-by-step explanation:
If S(x) is the position, the derivative S'(x) is the velocity.
Take the derivative using the chain rule:
Now, if the velocity = 0 then S'(x) = 0, and cos(x) must be 0 because the exponential is always different to 0.
In the interval [0, 2π] cos(x) = 0 when x= π/2 (90°) or x = 3π/2 (270°)
So the velocity equals 0 only 2 times in the interval [0, 2π]
Ответ:
number of green ÷ total number of marbles
times by
number of red ÷ total number of marbles left
so
(3/9) × (2/8) = (1/12)