Consider a continuous random variable x which has pdf fx(x) = 1/5, 0 < x < 5. chegg

Using the normal distribution principle, the Zscore which corresponds to the area under the normal curve at P(Z < z) = 0.9967 is 2.716

To obtain the Zscore in this scenario, which is the number of standard deviations from the mean value for a given score ; we make use of Zscore calculator or a normal distribution table ;

Using a normal distribution table;

Therefore, the Zscore value is 2.716

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