Mathematics: Consider square abcd with vertices at a(−8,19), b(2,−5), c(−22,−15), and d(−32,9). what is the area, in square units, of square abcd?

Consider square abcd with vertices at a(−8,19),

Ответ:

mmaglaya1

10.03.2022

Mathematics

$676units^{2}$

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a square, which is:

$A=s^{2}$

Where s is the lenght of a side of the square.

2. By definition, the sides of the square have equal lenghts. You can calculate the lenght of a side by calculating the distance between two vertices of the aquare:

$s_{AB}=\sqrt{(2-(-8))^{2}+(-5-19)^{2}}=26units$

Where $s_{AB}$ is the lenght of the side AB.

3. The area is:

$A=(26units)^{2}=676units^{2}$

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Ответ:

aprilkenedy12

02.11.2021

Mathematics

its D

Step-by-step explanation:

"i cant feel your vibe if you lie to me"

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Consider square abcd with vertices at a(−8,19), b(2,−5), c(−22,−15), and d(−32,9). what is the area, in square units, of square abcd?

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