Consider the equation 3tan^2(x)−1=0. the solutions of this equation over the interval {0,pi} are?

If we solve for tan(x) algebraically, we are then able to refer to the unit circle to find the solutions. Solving for tan(x) algebraically will give us tan(x) = (square root of 3)/3. On the unit circle, there are two possibilities with those coordinates: Pi/6 and 7pi/6

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Step-by-step explanation:

We have the following equation:

We use the property in our equation as follows:

and then, we use the identity :

As we are over the interval (0,pi) we use the positive value:

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First you need to find po8^2 + 6^2 = 64 + 36 = 100so po =  √100 = 10sin  x°  = oppo/ hypo sin  x°= 6/10 sin  x°= 3/5cos y° = adj / hypocos y° = 6/10cos y° = 3/5so sin  x° = cos y° = 3/5