Mathematics: Consider the following binomial experiment: A newspaper publisher claims that 52% of the people in a certain community read his newspaper. Doubting the assertion, a competitor randomly surveys 289 people in the community. Find the standard deviation of this experiment, if the newspaper publisher s claim is correct. a) 8.1932 b) 8.3932 c) 8.4932 d) 8.6932 e) 8.5932 f) None of the above.

Consider the following binomial experiment: A newspaper

youngboymark123

14.02.2022

SD = 8.4932

Step-by-step explanation:

Given

$Sample\ Size (n) = 289$

$proportion, p= 52\%$

Required

Determine the standard deviation (SD)

The standard deviation of a binomial distribution is calculated as thus:

$SD = \sqrt{np(1-p)}$

Substitute values for n and p

$SD = \sqrt{289 * 52\% * (1-52\%)}$

Convert to decimals

$SD = \sqrt{289 * 0.52 * (1-0.52)}$

$SD = \sqrt{289 * 0.52 * 0.48}$

$SD = \sqrt{72.1344}$

SD = 8.49319727782

SD = 8.4932 --- approximated

Hence, the calculated standard deviation is approximately 8.4932

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alext8691

03.04.2020

I don't know if this will help but here it is.

Step-by-step explanation:

Point A: (5,4)

Point B: (14,4)

Circle A Radius: 3

Circle B Radius: 6

I think this is how you do it.

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