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llolo8
16.09.2019 •
Mathematics
Consider the parabola represented by the equation -2y2 = 4x.
this parabola will open to the ?
.
the equation of the directrix of the parabola is ?
.
the focus of the parabola is ?
.
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Ответ:
The given expression is
If we rewrite this expression, it would be
Or, we can rewrite this way too
As you can observe, the quadratic variable is
not
, this change the orientation of the figure. Actually, this change a lot, because this parabola doesn't represent a function, because it will open horizontally, specifically, towards negative infinte, like the image attached shows.
If you do the vertical line test, you will see that such vertical line intercepts the figure in two points, which indicates that it's not a function.
Now, in this case, the directrix is defined as
, because the parabola is horizontal. Where
is the horizontal coordinate of the vertex, and
can be found as follows.
When, the parabola is horizontal is defined as
Where
are the coordinates of the vertex, which in this case is
. Also, particularly, we have that
So,
Then, the directrix would be
And the focus is defined as
![f(h+p,k)\\f(0+(-\frac{1}{2}),0)\\ f(-\frac{1}{2},0)](/tpl/images/0233/5416/f6056.png)
Therefore, the asnwer areThis parabola opens to the negative x-axis, as the image shows.The equation of the directrix is:Ответ:
5- x-coordinate
1- y-coordinate
y2-y1 over x2-x1 y=mx+b