Construct the line perpendicular to segment tu at point v. (1 point)

Draw a circle centered at point V

the circle will intersect TU at point  X and Y , then draw 2 circles , each centered at x and y with radius of VX

these 2 circles will intersect twice,  connect these points of intersection to draw your perendicular line

hope this helps

12 and 30 are two such given numbers.

Step-by-step explanation:

Here, given the LCM of both the numbers  = 60

The HCF of both the number = 6

Both number are greater then 6.

Now, as we know  LCM x HCF = Product of Two Numbers

⇒ 60 x 6 = 360 = Product of both numbers

Now, by the prime factorization of 360, we get:

360 =  2 x 2 x  2 x 3  x 3 x 5  = 12 x 30

Here, checking for the conditions:

(a) Both numbers 12 , 30 are greater than 6

(b)  HCF of 12 and 30  = 6

(c) LCM of 12 and 30 = 60

Hence, 12 and 30 are two such given numbers.