Decompose 6x/(x-4)(x+2) into partial fractions

We can write the equation    

Step-by-step explanation:

(x+4)  

2

3x+15

 =    

(x+4)  

2

3(x+4)+3

(x+4)  

2

3(x+4)+3

 =  

(x+4)

3

 +  

(x+4)  

2

3

So, there are total 2 terms.

The correct answer option is a) there are an infinite number of solutions

Step-by-step explanation:

We are given these two following equations:

15x = 5y - 5 --- (1)

y = 3x + 1 --- (2)

Solving these two by the substitution method by putting the value of y in equation (1).

15x = 5y - 5

15x = 5(3x + 1) - 1

15x = 15x + 5 - 5

5 and -5 get cancelled and we are left with 15 on both sides of the equation which will cancel each other.

Therefore, these equations have an infinite number of solutions.