zulfiquer5541
03.09.2021 •
Mathematics
Determine a equação reduzida de uma circunferência cujo centro é na origem e o raio é igual a raiz quadrada de 7 .
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Ответ:
1 2/21
Step-by-step explanation:
We start out with:
3/7 + 2/3
In order to add them together, they must have an equal denominator. An easy way to find an equal denominator is the cross method. We divide 7 by 3 and 3 by 7, giving us a denominator of 21:
3/21 + 2/21
But what about the numerators? You do the same thing as before (multiplying by the other's denominator). Now we have:
9/21 + 14/21
We add both together (the denominator stays the same) and we get 23. 23/21 is correct but not in simplest form. We remove 21 from the numerator (because it is a whole) and finally get:
1 2/21!
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