Mathematics: Determine the intervals on which the function f(x)=−7x2−7x+6f(x)=−7x2−7x+6 is concave up or down and find the points of inflection. (Use symbolic notation and fractions where needed. Give your answer as comma separated list. Enter NULL if there are no points of inflection.) Points of inflection: help (fractions) (Use symbolic notation and fractions where needed. Give your answers as intervals in the form (*,*). Use inf for infinity , U for combining intervals, and appropriate type of parenthesis

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Determine the intervals on which the function

amandaparrish2323

22.01.2022

Point of Inflection: Does not Existf(x) is concave up when x∈(-∞,-6)f(x) is concave down when x∈(-6, ∞)

Step-by-Step Explanation

We are to determine the intervals on which the function $f(x)=\frac{-7x^2-7}{x+6}$ is concave up or down and find the points of inflection.

A function f(x) is concave up in the intervals for which the second derivative of the function $\frac{d^{2}}{dx^{2}} 0$ .

A function f(x) is concave down in the intervals for which the second derivative of the function $\frac{d^{2}}{dx^{2}} < 0$ .

Given $f(x)=\frac{-7x^2-7}{x+6}$

We need to solve for the second derivative of the function.

The first derivative:

Using Quotient Rule:

$f^{'}(x)=\frac{14x(x+6)-(7x^2-7)}{(x+6)^{2}}$ .

$f^{'}(x)=\frac{7x^2+84x+7}{(x+6)^{2}}$ .

The Second derivative:

Similarly applying quotient rule:

$f^{''}(x )=\frac{(x+6)^{2}(14x+84)-( 7x^2+84x+7)(2x+12)}{(x+6)^{4}}$

$f^{''}(x)=\frac{14(x+6) (x+6) (x+6) -14(x+6)(x^2+12x+1) }{(x+6)^{4}}$

$f^{''}(x )=\frac{14(x+6) [(x+6) (x+6) -x^2+12x+1)] }{(x+6)^{4}}$

$f^{''}(x)=\frac{490 }{(x+6)^{3}}$

Now $f^{''}(x)=\frac{490 }{(x+6)^{3}} =0$ is 490, thus $f^{''}(x) =0$ does not have a solution,

However, we determine the point where $f^{''}(x)$ is undefined. This point is x=-6.

In the Interval, (-∞,-6), f(x) is concave Up and in the Interval (-6, ∞), f(x) is concave down. It has no Inflection point.

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