Evaluate (m) (x) for x = -3. (-3) = т n

m Sin[x] + n Cos[x] + p /. replacerule (* p + Sqrt[m^2 + n^2] Sin[x + ArcTan[m, n]] *) ... There are two or three tricks that we can use to solve for {a, b, c, ω} . First ... take the second derivative and evaluate both equatinos at x=0 and at x=π. ... Sin[b] -> σ, {ρ, σ}]; eq2 // Column Reduce[eq2, ω] (* { c n == n p, c ω^2 == p ω^2, n (-1 + ...

Step-by-step explanation:

To evaluate the clinical application of the second derivative of the fingertip photoplethysmogram waveform, we performed drug administration studies (study 1) and epidemiological studies (study 2). In study 1, ascending aortic pressure was recorded simultaneously with the fingertip photoplethysmogram and its second derivative in 39 patients with a mean+/-SD age of 54+/-11 years. The augmentation index was defined as the ratio of the height of the late systolic peak to that of the early systolic peak in the pulse. The second derivative consists of an a, b, c, and d wave in systole and an e wave in diastole. Ascending aortic pressure increased after injection of 2.5 microg angiotensin from 126/74 to 160/91 mm Hg and decreased after 0.3 mg sublingual nitroglycerin to 111/73 mm Hg. The d/a, the ratio of the height of the d wave to that of the a wave, decreased after angiotensin from -0.40+/-0.13 to -0.62+/-0.19 and increased after nitroglycerin to -0.25+/-0.12 (P<0.001 and P<0.001, respectively). The negative d/a increased with increases in plethysmographic and ascending aortic augmentation indices (r=0.79, P<0.001, and r=0.80, P<0.001, respectively). The negative d/a reflects the late systolic pressure augmentation in the ascending aorta and may be useful for noninvasive evaluation of the effects of vasoactive agents. In study 2, the second derivative of the plethysmogram waveform was measured in a total of 600 subjects (50 men and 50 women in each decade from the 3rd to the 8th) in our health assessment center

21 ounces

Step-by-step explanation:

We will set up a proportion for this problem.  First we use the ratio we are given of sugar to flour:

10/3

The second ratio will be int he same format, sugar to flour.  We know we are using 70 ounces of sugar, and an unknown amount of flour (we will use x):

70/x

This gives us the proportion

10/3 = 70/x

Cross-multiply:

10(x) = 3(70)

10x = 210

Divide both sides by 10:

10x/10 = 210/10

x = 21