Mathematics: Explain the process for solving this logarithm. show all steps! log3 x + log3 4 – 2log3 3 = 2 *note it s log base 3. the farthest i ve got is log3 (x * 4/9) = 2. but i don t know where to go from here!

Explain the process for solving this logarithm.

Ответ:

xxtonixwilsonxx

01.08.2019

$\begin{aligned} \log_3 x + \log_3 4 - 2\log _3 3 & =2\\ \log_3 (x\cdot 4) - \log _3 3^2 & =2\\ \log_3 \left(\frac{4x}{9}\right) & =2\end{aligned}$ convert from logarithmic form to exponential form, aka $a^b = c \leftrightarrow \log_a(c) = b$ this is the relationship between logarithmic form and exponential form (of an equation).so converting: $\begin{aligned} \log_3 \left(\frac{4x}{9}\right) & =2 \\ 3^2 & = \frac{4x}{9} \\ 9 & = \frac{4x}{9} \\ 81 & = 4x \\ x & = \frac{81}{4} \end{aligned}$ x = 81/4

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Ответ:

chiefkeef5330

01.01.2020

Mathematics

5 *22 is 110 if not then wee

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Explain the process for solving this logarithm. show all steps! log3 x + log3 4 – 2log3 3 = 2 note it's log base 3. the farthest i've got is log3 (x 4/9) = 2. but i don't know where to go from here!

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Explain the process for solving this logarithm. show all steps! log3 x + log3 4 – 2log3 3 = 2 *note it's log base 3. the farthest i've got is log3 (x * 4/9) = 2. but i don't know where to go from here!

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Explain the process for solving this logarithm. show all steps! log3 x + log3 4 – 2log3 3 = 2 note it's log base 3. the farthest i've got is log3 (x 4/9) = 2. but i don't know where to go from here!