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torresxavier86osxdrx
28.07.2019 •
Mathematics
Factor completely and then place the factors in the proper location on the grid. 8c 2 - 26c + 15 find the greatest common factor of 270 and 360. (give the answer in the numerical form in the top box and in exponential form by filling in the boxes for exponents.) [] 2[]*3[]*5[] (these are where the exponents go[]) find the greatest common factor of 8 a3b2 and 12 ab4 . [] a[]b[] factor completely and then place the factors in the proper location on the grid. 81a 2 + 36a + 4 factor the four-term polynomial. mn - 15 + 3 m - 5 n (m + 3)(n - 5) (n - 3)(m - 5) (n + 3)(m - 5)
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Ответ:
2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.
4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.
5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)
Hope this helped :) Have a great day
Ответ:
1.![(2c-5)(4c-3)](/tpl/images/0140/9437/888d3.png)
2.![2\times 3^2\times 5](/tpl/images/0140/9437/cb114.png)
3.![4ab^2](/tpl/images/0140/9437/16b87.png)
4.![(9a+2)(9a+2)](/tpl/images/0140/9437/ed8aa.png)
4.![(m-5)(n+3)](/tpl/images/0140/9437/0c007.png)
Step-by-step explanation:
1.We are given that
We have to find the factor
Using factorization method
2.We are given that 270 and 360
We have to find the HCF of 270 and 360
Hence, HCF of 270 and 360 =![2\times 3^2\times 5](/tpl/images/0140/9437/cb114.png)
3.We are given that
and ![12ab^4](/tpl/images/0140/9437/0143e.png)
We have to find HCF
Common factors are 4,a,![b^2](/tpl/images/0140/9437/bfb8c.png)
Hence,HCF
and![12 ab^4 =4ab^2](/tpl/images/0140/9437/0d108.png)
4.![81a^2+36a+4](/tpl/images/0140/9437/ed29c.png)
We have to find the factors
5.![mn-15+3m-5n](/tpl/images/0140/9437/0943d.png)
We have to find the factors
Ответ:
its is actually 4
Step-by-step explanation: