dv2200342
21.07.2019 •
Mathematics
Factor completely: x^40–x^20 y^24+y^8 a^20–a^10+a^5 b^60+b^40–b^20 (^=to the power of)
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Ответ:
2) y^24+y^8 = y^8(y^16 + 1)
3) a^20–a^10+a^5 = a^5(a^15 - a^5 + 1)
4) b^60+b^40–b^20 = b^20(b^40 + b^20 - 1)
Hope this helps!
Ответ:
A?
Step-by-step explanation: