Factor the expression below. x2 - 6x + 9 a. 3(x2 - 2x + 3) b. (x - 3)(x + 3) c. (x + 3)(x + 3) d. (x - 3)(x - 3)

For this case we must factor the following quadratic expression:

To factor, we must find two numbers that when multiplied give as result +9 and when added or subtracted give as result -6.

These numbers are:

-3 and -3

So, we have:

Option D

D. (x - 3)(x - 3)

Step-by-step explanation:

We are given the following expression and we are to factorize it:

Finding factors of positive 9 such that when added they give a result of -6.

Factorizing them to get: