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Gipson
31.07.2019 •
Mathematics
Find an equation for the line thatis tangent to the curve y=5x^3-5x at the point (1,0)
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Ответ:
The gradient of a tangent can be found by differentiating the equation:
Subbing in the x value of 1, the gradient therefore is 15-5 = 10, giving us m in our general equation for a line y=mx+c, i.e. y = 10x + c
We know at x=1, y is 0. Subbing this in:
0 = 10 + c, and solving for c = -10
Therefore, the equation of the tangential line at (1,0) is
Ответ:
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Step-by-step explanation: