Find each measure.
ML=
JLK=
JLM=
MJ=

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Ответ:

ogneshelle

03.03.2021

Mathematics

Solution:-

Given that length of rectangle is 3 ft more than its breadth . Also , perimeter of rectangle is 62 ft . And we are asked to find the Length and breadth .

So , we know we can find perimeter of rectangle as :

$\boxed{\red{\bf \dag Permiter_{rectangle}=2(l+b)}}$

Now , let us take the

Breadth be x .Length be x + 3 .

So , as per Question :

$\tt :\implies Perimeter=2(l+b)$

$\tt :\implies 62 \cancel{ft.} = 2( x + 3 + x ) \cancel{ft.}$

$\tt :\implies 62 = 2 ( 2x + 3 )$

$\tt :\implies 62 = 4x + 6$

$\tt :\implies 4x = 62 - 6$

$\tt :\implies4x = 56.$

$\tt :\implies x =\dfrac{\cancel{56}}{\cancel{4}}$

$\underline{\boxed{\red{\tt\longmapsto \:\:x\:\:=\:\:14}}}$

Hence we got x as 14 .

So , let's put the value in our assumption:

$\boxed{\green{\bf \pink{\dag} Length = x + 3 = 14 + 3 = 17 ft.}}$ $\boxed{\green{\bf \pink{\dag} Breadth = x = 14 ft.}}$

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Find each measure. ML= JLK= JLM= MJ=