PAADUUUgma

PAADUUUgma

20.01.2022 •

Mathematics

Find the 26th term of AP 20,10,0- 10

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Ответ:

nmknightp02

09.09.2022

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$\sqrt{ ({12 \sqrt{3} })^{2} + {12}^{2} } =$

$\sqrt{(144 \times 3) + 144} =$

$\sqrt{4 \times 144} =$

$\sqrt{ {2}^{2} \times {12}^{2} } =$

$\sqrt{ ({2 \times 12})^{2} } =$

$\sqrt{ {24}^{2} } = 24$

Thus :

BC = Hypotenuse = 24

We know that the facing angle to the Hypotenuse has a measure of 90°.

Thus :

A =90°

So ∆ ABC is a right triangle .

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Look :

$\sin( B) = \frac{AC}{BC} \\$

$\sin(B) = \frac{12 \sqrt{3} }{24} \\$

$\sin(B) = \frac{12 \times \sqrt{3} }{12 \times 2} \\$

$\sin(B) = \frac{ \sqrt{3} }{2} \\$

So Angle B has a measure of 60° ;

Because :

$\sin(60°) = \frac{ \sqrt{3} }{2} \\$

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Sum of the interior angles of any triangle equal 180°.

Thus :

A + B + C = 180°

90° + 60° + C = 180°

C + 150° = 180°

Subtract sides 150°

$C + 150° - 150° = 180° - 150° \\$

C = 30°

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So the correct answer is Option Two .

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