Find the equation of a line parallel to y=-10x-5 passing through the coordinate (-3,5)

With a given parallel line and a given point on the line
we can use the point-line method:  y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.

Here
m=-10, k=-5, (x0,y0)=(-3,5)

=> the required line L is given by:
L:  y-5=-10(x-(-3))

on simplification
L: y=-10x-30+5
L: y=-10x-25

They all have a straight edges