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angvtl02
04.10.2019 •
Mathematics
Find the perimeter of a square whose diagonal is 8 feet. round to the nearest tenth if needed.
math test tomorrow
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Ответ:
Hello from MrBillDoesMath!
22.6
Discussion:
From the attachment, the square has sides of length "x", and the Pythagorean theorem applies. Hence
x^2 + x^2 = 8^2 =>
2 x^2 = 8^2 => divide both sides by 4
x^2 = 8^2/2 => 8^2 = 64, 8^2/2 = 32
x^2 = 32 =>
x = sqrt(32) = => as 32 = 16 * 2
x = sqrt(16) * sqrt(2) =>
x = 4 sqrt(2)
The perimeter is 4*x
= 4*(4 sqrt(2) )
= 16 * sqrt(2) => as sqrt(2) is approx 1.41
= 22.6
Thank you,
MrB
Ответ:
Answer
v = 1000 cubic cm
Step-by-step explanation:
The formula for Volume of Cube is V =![s^{3}](/tpl/images/0604/5223/f4ee5.png)
in this case the sides are 10 cm so we plug in the numbers
v =![10^{3}](/tpl/images/0604/5223/838fb.png)
v = 1000 cubic cm