Find the sum. (-7/2z+4)+(1/5z-15)

-(33+110z)/10z

Step-by-step explanation:

(-7/2z +4)+(1/5z -15)

from BODMAS, solving the one in the bracket

First(-7/2z +4)+(1/5z -15)

Find the Lcm

[-7/2z +4] +[1/5z -15]

(7+8z)/2z +(1-75z)/5z

find the Lcm which is 10z

[5(-7+8z) + 2(1-75z)]/10z

[(-35+40z)+(2-150z)]10z

(-35+2+40z-150z)/10z

(-33-110z)/10z

-(33+110z)/10z

choice A m

Step-by-step explanation:

n= 1

m= 7

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