Find the sum of 6 σ 2 3(0.5)^n-1. show work.

Step-by-step explanation:

Unfortunately it's not clear what you mean by 6 Σ 2 3(0.5)^n-1.  I am going to assume that you mean summing up from n = 2 to n = 6 of the expression 3(0.5)^(n-1).  Note that the "n-1" must be enclosed in parentheses.

a(2) = 3(0.5)^(2 -1) = 3(0.5) = 1.5

a(3) =  3(0.5)^(3 -1) = 3(0.5)^2 = 0.75

a(4) = 3(0.5)^(4 -1) = 3(0.5)^3 = 0.375

a(5) = 0.1875

a(6) = 0.09375

Sum these up to find the final answer.

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