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24.06.2019 •
Mathematics
Find the value of k such that the quadratic polynomials x2-(k+6)x+2(2k+1) as sum of the zeroes as the half of their product
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Ответ:
k = 5
Step-by-step explanation:
The sum of the zeros is the opposite of the coefficient of x, so is (k+6).
The product of zeros is the constant term, 2(2k+1), so half their product is (2k+1).
The problem statement asks us to find k so that these values are the same:
k +6 = 2k +1
5 = k . . . . . . . . subtract k+1
The value of k is 5.
The zeros are 5.5±√8.25. Their sum is 11; their product is 22.
Ответ:
I think 4 days...
Step-by-step explanation:
Don't no whether it is correct...bcoz the sum is not clear to understand