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13.12.2020 •
Mathematics
Find the value of X for which log X, log (X+2) and log (X+16) are three consecutive terms of an arithmetic series.
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Ответ:
x=-2
Step-by-step explanation:
log x, log (x+2) , log (x+16) are in A.P.
2log (x+2)=log (x+2) +log (x+16)
log (x+2)²=log [(x+2)(x+16)]
(x+2)²=(x+2)(x+16)
x²+4x+4=x²+2x+16x+32
4x-18x=32-4
-14x=28
x=28/(-14)=-2
Ответ:
Here is what I got