60744
05.05.2020 •
Mathematics
Find the vector equations for medians from the vertices to the three midpoints of triangle ABC with vertices A(-1,5), B(5,-2) and C(3,5).
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Ответ:
The equation is
2y + 85x + 75 = 0
Step-by-step explanation:
Given vertices A(-1,5), B(5,-2) and C(3,5).
Suppose we want to find the median from A
First, we find the midpoint of side BC
Let the midpoint be M = ((x1 + x2)/2, (y1 + y2)/2)
= ((5+3)/2, (-2-5)/2)
= (8/2, -7/2)
= (4, -7/2)
Next, we write the equation of median with A(-1,5) and midpoint M(4,-7/2)
y = mx + c
The slope m = (y2 - y1)/(x2 - x1)
= (-7/2 - 5)/(4 + 1)
= (-17/2)/5
m = -85/2
We find the y-intercept, using A(-1,5)
x = -1, y = 5, m = -85/2
y = mx + c
5 = (-85/2)(-1) + c
c = 5- 85/2
= -75/2
y = -85x/2 - 75/2
Multiply through by 2
2y = -85x - 75
2y + 85x + 75 = 0
And this is the equation
Ответ:
53.06/2 = 26.53 = c