Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to five. . which equation could be used to determine the number? . 1/2(n - 2) + 2/5 n = 5. 1/2(n + 2) - 2/5 n = 5. 1/2(n + 2) + 2/5 n = 5

Then, it would be: 1/2 (n+2) - 2/5 n = 5

So, OPTION B is your answer

 The correct option is (B)

Step-by-step explanation:  We are given to select the correct equation to determine two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to five.

Let, 'n' and '(n + 2)' be the two consecutive even numbers.

Then, according to the given information, the equation can be written as

So, n = 40  and  n + 2 = 40 + 2 = 42.

Thus, the two even numbers are 40 and 42.

And, the required equation is

Option (B) is correct.

18

Step-by-step explanation:

P (Parenthesis)     (2^3+4^2)  4^2=16 | 2^3= 8

E (Exponents)                             16+8=24

M (Multiply)                                 2/4=.75

D (Divide)                                  .75x24=18

A (Add)

S (Subtract)