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tiannaetzel
24.01.2020 •
Mathematics
Johnny uses a wheelbarrow to move planting soil to a delivery truck. the volume of planting soil that fits in the wheelbarrow measures 2 feet by 3feet by 1.5 feet. the delivery truck measures 11 feet by 8 feet and is 6 feet tall. johnny puts soil in the delivery truck until its 70% full. what is the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full?
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Ответ:
V=W*L*H
2*3*1.5= 9 wheelbarrow
11*8*6=528 truck
find the amount of 70% of the truck so
528*.7=369.6
369.6/9= 41.06 times
Ответ:
41 times.
Step-by-step explanation:
We have,
A delivery truck measures 11 feet by 8 feet and is 6 feet tall.
⇒ Volume of the truck = 11 × 8 × 6 = 528 ft³,
Now, the volume of planting soil that fits in the wheelbarrow measures 2 feet by 3 feet by 1.5 feet.
⇒ Volume of planting soil = 2 × 3 × 1.5 = 9 ft³,
Let n be the number of times johnny needs to use the wheelbarrow until the truck is 70% full,
⇒ Volume of planting soil × n = 70 % of the volume of the truck
Hence, the minimum number of times johnny needs to use the wheelbarrow until the truck is 70% full is 41.
Ответ:
Angle 8 = 60°
Step-by-step explanation:
See the attached diagram.
The measurement of angle 2 is 60°.
Now, angle 2 = angle 4 as they are equal vertically opposite angles.
Hence, angle 4 = 60°
Now, horizontal lines AB ║ CD and the inclined line is the transverse line.
Hence, angle 4 and angle 8 are corresponding angles.
Therefore, angle 4 = angle 8 = 60° (Answer)