Mathematics: For accounting purposes, the value of assets (land, buildings, equipment) in a business are depreciated at a set rate per year. the value, v(t), of $775,000 worth of assets after t years, that depreciate at 15% per year, is given by the formula v(t) = v0(b)t. what is the value of vo and b, and when rounded to the nearest cent, what are the assets valued at after 6 years? vo = $775,000, b = 0.85, and the value after 6 years is $289,324.17 vo = $775,000, b = 0.15, and the value after 6 years is $8.82

ANSWER: $720, 6, 720 by 6, $120Step-by-step explanation:...

For accounting purposes, the value of assets (land,

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05.01.2022

Vo = $775,000, b = 0.85, and the value after 6 years is $292,290.87

Step-by-step explanation:

The formula $V(t)=Vo(b)^{t}$

Vo is the value of assets = $775000

b = 1-r

r = rate of depreciation = 15% or 0.15

b =1−0.15=0.85

T= time ( number of years ) = 6

So after 6 years the value of the assets will be :

V(6)= $775000*(0.85)^{6}$

= 775000*0.37714 = $292283.50

This is closest to $292,290.87, therefore, option D is the answer.

Vo = $775,000, b = 0.85, and the value after 6 years is $292,290.87

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