Given: △akm, kd ⊥ am , ak = 6, km = 10, m∠akm = 93º find: kd

The measure of the perpendicular KD is 8.72 unit .

Step-by-step explanation:

Given as :

The triangle AKM  , with KD perpendicular to AM

The measure of side AK = 6 unit

The measure of side KM = 10 unit

The ∠ AKM = 93°

Let The measure of side KD = x unit

Now,

∵ KD ⊥ AM , KD divide the angle  ∠ AKM  equally

So,  ∠ AKD =  ∠

I.e  ∠ AKD =  ∠

∴  ∠ AKD = 46.5°

Now, Again

Cos Ф =  

I.e Cos 46.5° =

I.e 0.688 =

∴ KD =

I.e KD = 8.72 unit

Hence The measure of the perpendicular KD is 8.72 unit  Answer

If x+2 equals 5 then it would be x+2-2=5-2, so x= 3

Then you would plug it in and it would be 3(3+2) + 3(3+2)

Simplify it to 3(5) + 3(5)

Then multiply and it would be 15 + 15= 30  

30 is your final answer.

Hope this helped!